JEE Main 202127 Jul, Morning shiftMathematicsMediumTrigonometry118× since 2002If sinθ+cosθ=12\sin \theta + \cos \theta = {1 \over 2}sinθ+cosθ=21, then 16(sin(2θ\thetaθ) + cos(4θ\thetaθ) + sin(6θ\thetaθ)) is equal to :AOption A. 23BOption B. −-−27COption C. −-−23DOption D. 27CheckSkip · show solution