JEE Main 20199 Jan, Morning shiftMathematicsHardTrigonometry118× since 2002For any θ∈(π4,π2)\theta \in \left( {{\pi \over 4},{\pi \over 2}} \right)θ∈(4π,2π), the expression 3(cosθ−sinθ)43{(\cos \theta - \sin \theta )^4}3(cosθ−sinθ)4+6(sinθ+cosθ)2+4sin6θ+ 6{(\sin \theta + \cos \theta )^2} + 4{\sin ^6}\theta+6(sinθ+cosθ)2+4sin6θ equals :AOption A. 13 – 4 cos²θ\thetaθ + 6sin²θ\thetaθcos²θ\thetaθBOption B. 13 – 4 cos⁶θ\thetaθCOption C. 13 – 4 cos²θ\thetaθ + 6cos²θ\thetaθDOption D. 13 – 4 cos⁴θ\thetaθ + 2sin²θ\thetaθcos²θ\thetaθCheckSkip · show solution
