JEE Main 2004Annual, Paper 1PhysicsEasyElectronic Devices66× since 2002For a transistor amplifier in common emitter configuration for load impedance of 1k Ω1k\,\Omega1kΩ (hfe=50\left( {{h_{fe}} = 50} \right.(hfe=50 and hoe=25)\left. {{h_{oe}} = 25} \right)hoe=25) the current gain isAOption A. −24.8-24.8−24.8BOption B. −15.7-15.7−15.7COption C. −5.2-5.2−5.2DOption D. −48.78-48.78−48.78CheckSkip · show solution