For a plane electromagnetic wave, the magnetic field at a point x and time t is B (x,t) = [ 1.2 × 10⁻⁷ sin (0.5 × 10³x + 1.5 × 10¹¹t) k ] T The instantaneous electric field E corresponding to B is: (speed of light c = 3 × 10⁸ ms^–1)

(D) E (x,t) = [ - 36 sin (0.5 × 10³x + 1.5 × 10¹¹t) j ]V/m

(A) E (x,t) = [ 36 sin (1 × 10³x + 1.5 × 10¹¹t) i ] V/m

(B) E (x,t) = [ 36 sin (0.5 × 10³x + 1.5 × 10¹¹t) k ]V/m

(C) E (x,t) = [ 36 sin (1 × 10³x + 0.5 × 10¹¹t) j ]V/m

Electromagnetic Waves: JEE Main 2020 Physics question

JEE Main 2020 · 6 Sep, Evening shift · Q6761

JEE Main 20206 Sep, Evening shiftPhysicsMediumElectromagnetic Waves120× since 2002

For a plane electromagnetic wave, the magnetic field at a point x and time t is

\overrightarrow B \left( {x,t} \right)

\left[ {1.2 \times {{10}^{ - 7}}\sin \left( {0.5 \times {{10}^3}x + 1.5 \times {{10}^{11}}t} \right)\widehat k} \right]

T The instantaneous electric field

\overrightarrow E

corresponding to

\overrightarrow B

is : (speed of light c = 3 × 10⁸ ms^–1)

JEE Main 2020 Electromagnetic Waves Question with Solution (6 Sep Evening shift, Q6761) | JEE Arc