Electromagnetic Waves — JEE Main 2015 · 10 Apr, Morning shift · Q6738

Question

An electromagnetic wave travelling in the x-direction has frequency of 23 × 10¹⁴ Hz and electric field amplitude of 27 Vm⁻¹. From the options given below, which one describes the magnetic field for this wave ?

Accepted Answer

(B) B (x, t) = (9 × 10⁻⁸T) k sin [ 2 π (1.5 × 10⁻⁶x - 2 × 10¹⁴t)]

Answer

(A) B (x, t) = (3 × 10⁻⁸T) j sin [ 2 π (1.5 × 10⁻⁸x - 2 × 10¹⁴t)]

Answer

(C) B (x, t) = (9 × 10⁻⁸T) i sin [ 2 π (1.5 × 10⁻⁸x - 2 × 10¹⁴t)]

Answer

(D) B (x, t) = (9 × 10⁻⁸T) j sin [(1.5 × 10⁻⁶ x - 2 × 10¹⁴t)]

Electromagnetic Waves: JEE Main 2015 Physics question

More on Electromagnetic Waves

Electromagnetic Waves: JEE Main 2015 Physics question

More on Electromagnetic Waves