A substance 'X' (1.5 g) dissolved in 150 g of a solvent 'Y' (molar mass = 300 g mol ⁻¹) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent 'Y' is _ _ _ ×10⁻². (nearest integer) [Given: K b of the solvent = 5.0 K kg mol ⁻¹ ] Assume the solution to be dilute and no association or dissociation of X takes place in solution.

Solutions: JEE Main 2026 Chemistry question

JEE Main 2026 · 21 Jan, Evening shift · Q73

JEE Main 202621 Jan, Evening shiftChemistryHardSolutions71× since 2002

A substance 'X' (1.5 g) dissolved in 150 g of a solvent 'Y' (molar mass = 300 g mol

^{-1}

) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent 'Y' is ______

\times10^{-2}

. (nearest integer) [Given :

K_b

of the solvent = 5.0 K kg mol

^{-1}

] Assume the solution to be dilute and no association or dissociation of X takes place in solution.

Your answerType your answer. Integers and decimals are accepted.