JEE Main 202229 Jun, Morning shiftMathematicsMediumTrigonometry118× since 200250tan(3tan−1(12)+2cos−1(15))+42tan(12tan−1(22))50\tan \left( {3{{\tan }^{ - 1}}\left( {{1 \over 2}} \right) + 2{{\cos }^{ - 1}}\left( {{1 \over {\sqrt 5 }}} \right)} \right) + 4\sqrt 2 \tan \left( {{1 \over 2}{{\tan }^{ - 1}}(2\sqrt 2 )} \right)50tan(3tan−1(21)+2cos−1(51))+42tan(21tan−1(22)) is equal to ____________.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution