JEE Main 20203 Sep, Morning shiftMathematicsMediumTrigonometry118× since 20022π\piπ - (sin−145+sin−1513+sin−11665)\left( {{{\sin }^{ - 1}}{4 \over 5} + {{\sin }^{ - 1}}{5 \over {13}} + {{\sin }^{ - 1}}{{16} \over {65}}} \right)(sin−154+sin−1135+sin−16516) is equal to :AOption A. 7π4{{7\pi } \over 4}47πBOption B. 5π4{{5\pi } \over 4}45πCOption C. 3π2{{3\pi } \over 2}23πDOption D. π2{\pi \over 2}2πCheckSkip · show solution
