JEE Main 202226 Jun, Evening shiftMathematicsEasyTrigonometry118× since 200216sin(20∘)sin(40∘)sin(80∘)16\sin (20^\circ )\sin (40^\circ )\sin (80^\circ )16sin(20∘)sin(40∘)sin(80∘) is equal to :AOption A. 3\sqrt 33BOption B. 23\sqrt 33COption C. 3DOption D. 43\sqrt 33CheckSkip · show solution
