JEE Main 202311 Apr, Evening shiftPhysicsMediumKinematics177× since 2002When vector A⃗=2i^+3j^+2k^\vec{A}=2 \hat{i}+3 \hat{j}+2 \hat{k}A=2i^+3j^+2k^ is subtracted from vector B→\overrightarrow{\mathrm{B}}B, it gives a vector equal to 2j^2 \hat{j}2j^. Then the magnitude of vector B→\overrightarrow{\mathrm{B}}B will be :AOption A. 3BOption B. 33\sqrt{33}33COption C. 6\sqrt66DOption D. 5\sqrt55CheckSkip · show solution
