Dual Nature of Matter and Radiation: JEE Main 2020 Physics question

When photon of energy 4.0 eV strikes the surface of a metal A, the ejected photoelectrons have maximum kinetic energy T_A eV end de-Broglie wavelength $\lambda _A$. The maximum kinetic energy of photoelectrons liberated from another metal B by photon of energy 4.50 eV is T_B = (T_A – 1.5) eV. If the de-Broglie wavelength of these photoelectrons $\lambda _B$ = 2$\lambda _A$, then the work function of metal B is :