When
C u 2 + \mathrm{Cu}^{2+} Cu 2 + ion is treated with
K I \mathrm{KI} KI , a white precipitate,
X \mathrm{X} X appears in solution. The solution is titrated with sodium thiosulphate, the compound
Y \mathrm{Y} Y is formed.
X \mathrm{X} X and
Y \mathrm{Y} Y respectively are :
A Option A. .tg {border-collapse:collapse;border-spacing:0;}
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X = C u I 2 \mathrm{X=CuI_2} X = Cu I 2 Y = N a 2 S 4 O 6 \mathrm{Y=Na_2S_4O_6} Y = N a 2 S 4 O 6 B Option B. .tg {border-collapse:collapse;border-spacing:0;}
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X = C u 2 I 2 \mathrm{X=Cu_2I_2} X = C u 2 I 2 Y = N a 2 S 4 O 6 \mathrm{Y=Na_2S_4O_6} Y = N a 2 S 4 O 6 C Option C. .tg {border-collapse:collapse;border-spacing:0;}
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X = C u I 2 \mathrm{X=CuI_2} X = Cu I 2 Y = N a 2 S 2 O 3 \mathrm{Y=Na_2S_2O_3} Y = N a 2 S 2 O 3 D Option D. .tg {border-collapse:collapse;border-spacing:0;}
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X = C u 2 I 2 \mathrm{X=Cu_2I_2} X = C u 2 I 2 Y = N a 2 S 4 O 5 \mathrm{Y=Na_2S_4O_5} Y = N a 2 S 4 O 5 Check Skip · show solution
