JEE Main 2003Annual, Paper 1PhysicsEasyAtoms and Nuclei183× since 2002When a U238{U^{238}}U238 nucleus originally at rest, decays by emitting an alpha particle having a speed ′u′,'u',′u′, the recoil speed of the residual nucleus isAOption A. 4μ238{{4\mu } \over {238}}2384μBOption B. −4μ234- {{4\mu } \over {234}}−2344μCOption C. 4μ234{{4\mu } \over {234}}2344μDOption D. −4μ238- {{4\mu } \over {238}}−2384μCheckSkip · show solution
