JEE Main 20245 Apr, Evening shiftPhysicsHardUnits and Measurements122× since 2002What is the dimensional formula of ab−1a b^{-1}ab−1 in the equation (P+aV2)(V−b)=RT\left(\mathrm{P}+\frac{\mathrm{a}}{\mathrm{V}^2}\right)(\mathrm{V}-\mathrm{b})=\mathrm{RT}(P+V2a)(V−b)=RT, where letters have their usual meaning.AOption A. [M6 L7 T4][\mathrm{M}^6 \mathrm{~L}^7 \mathrm{~T}^4][M6 L7 T4]BOption B. [M−1 L5 T3][\mathrm{M}^{-1} \mathrm{~L}^5 \mathrm{~T}^3][M−1 L5 T3]COption C. [M0 L3 T−2][\mathrm{M}^0 \mathrm{~L}^3 \mathrm{~T}^{-2}][M0 L3 T−2]DOption D. [ML2 T−2][\mathrm{ML}^2 \mathrm{~T}^{-2}][ML2 T−2]CheckSkip · show solution
