JEE Main 201910 Jan, Evening shiftPhysicsMediumKinematics177× since 2002Two vectors A→\overrightarrow AA and B→\overrightarrow BB have equal magnitudes. The magnitude of (A→+B→)\left( {\overrightarrow A + \overrightarrow B } \right)(A+B) is 'n' times the magnitude of (A→−B→)\left( {\overrightarrow A - \overrightarrow B } \right)(A−B) . The angle between A→{\overrightarrow A }A and B→{\overrightarrow B }B is -AOption A. sin−1[n−1n+1]{\sin ^{ - 1}}\left[ {{{n - 1} \over {n + 1}}} \right]sin−1[n+1n−1]BOption B. sin−1[n2−1n2+1]{\sin ^{ - 1}}\left[ {{{{n^2} - 1} \over {{n^2} + 1}}} \right]sin−1[n2+1n2−1]COption C. cos−1[n2−1n2+1]{\cos ^{ - 1}}\left[ {{{{n^2} - 1} \over {{n^2} + 1}}} \right]cos−1[n2+1n2−1]DOption D. cos−1[n−1n+1]{\cos ^{ - 1}}\left[ {{{n - 1} \over {n + 1}}} \right]cos−1[n+1n−1]CheckSkip · show solution
