Two sources of equal emfs are connected in series. This combination is connected to an external resistance R. The internal resistances of the two sources are r₁ and r₂ (r₁>r₂). If the potential difference across the source of internal resistance r₁ is zero, then the value of R will be:

Current Electricity: JEE Main 2022 Physics question

JEE Main 2022 · 27 Jul, Morning shift · Q6394

JEE Main 202227 Jul, Morning shiftPhysicsMediumCurrent Electricity150× since 2002

Two sources of equal emfs are connected in series. This combination is connected to an external resistance R. The internal resistances of the two sources are

r_{1}

and

r_{2}

\left(r_{1}>r_{2}\right)

. If the potential difference across the source of internal resistance

r_{1}

is zero, then the value of R will be :

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