Two sources of equal emf are connected to an external resistance R. The internal resistance of the two sources are R₁ and R₂(R₁ > R₁). If the potential difference across the source having internal resistance R₂ is zero, then

(B) R = R₂ × (R₁ + R₂)/(R₂ - R₁)

Current Electricity: JEE Main 2005 Physics question

JEE Main 2005 · Annual, Paper 1 · Q6487

JEE Main 2005Annual, Paper 1PhysicsMediumCurrent Electricity150× since 2002

Two sources of equal

emf

are connected to an external resistance

R.

The internal resistance of the two sources are

{R_1}

and

{R_2}\left( {{R_1} > {R_1}} \right).

If the potential difference across the source having internal resistance

{R_2}

is zero, then

JEE Main 2005 Current Electricity Question with Solution (Annual Paper 1, Q6487) | JEE Arc