Two salts A₂X and MX have the same value of solubility product of 4.0 × 10⁻¹2. The ratio of their molar solubilities i.e. (S(A₂X))/(S(MX)) = _ _ _ _ _. (Round off to the Nearest Integer)

Equilibrium: JEE Main 2021 Chemistry question

JEE Main 2021 · 16 Mar, Morning shift · Q13

JEE Main 202116 Mar, Morning shiftChemistryMediumEquilibrium123× since 2002

Two salts A₂X and MX have the same value of solubility product of 4.0

\times

10^

-

12. The ratio of their molar solubilities i.e.

{{S({A_2}X)} \over {S(MX)}}

= __________. (Round off to the Nearest Integer)

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2021 Equilibrium Question with Answer (16 Mar Morning shift, Q13) | JEE Arc