JEE Main 202522 Jan, Evening shiftChemistryMediumOrganic Compounds Containing Oxygen65× since 2003Toluene (excess) →(ii) H3O+ (iii) NaHSO3(i) CrO2Cl2,CS2\xrightarrow[\text{(ii) } \mathrm{H_3O^+} \text{ (iii) } \mathrm{NaHSO_3}]{\text{(i) } \mathrm{CrO_2Cl_2, CS_2}}(i) CrO2Cl2,CS2(ii) H3O+ (iii) NaHSO3 Filter →\to→ Residue (A) Residue (A) + HCl(dil) →\to→ Compound (B) Structure of residue (A) and compound (B) formed respectively is :AOption A. A = benzaldehyde (C6H5CHO\mathrm{C_6H_5CHO}C6H5CHO); B = benzoic acid (C6H5COOH\mathrm{C_6H_5COOH}C6H5COOH)BOption B. A = benzaldehyde (C6H5CHO\mathrm{C_6H_5CHO}C6H5CHO); B = sodium benzoate (C6H5COONa\mathrm{C_6H_5COONa}C6H5COONa)COption C. A = C6H5CH(OH)SO3Na\mathrm{C_6H_5CH(OH)SO_3Na}C6H5CH(OH)SO3Na (bisulphite adduct); B = benzaldehyde (C6H5CHO\mathrm{C_6H_5CHO}C6H5CHO)DOption D. A = C6H5CH(OCrOHCl2)2\mathrm{C_6H_5CH(OCrOHCl_2)_2}C6H5CH(OCrOHCl2)2; B = benzaldehyde (C6H5CHO\mathrm{C_6H_5CHO}C6H5CHO)CheckStep-by-step hintSkip · show solution