Three perfect gases at absolute temperatures T₁, T₂ and T₃ are mixed. The masses of molecules are m₁,m₂ and m₃ and the number of molecules are n₁, n₂ and n₃ respectively. Assuming no loss of energy, the final temperature of the mixture is:

(A) (n₁T₁ + n₂T₂ + n₃T₃)/(n₁ + n₂ + n₃)

(B) (n₁T₁² + n₂T₂² + n₃T₃²)/(n₁T₁ + n₂T₂ + n₃T₃)

(C) (n₁²T₁² + n₂²T₂² + n₃²T₃²)/(n₁T₁ + n₂T₂ + n₃T₃)

Thermodynamics: JEE Main 2011 Physics question

JEE Main 2011 · Annual, Paper 1 · Q7289

JEE Main 2011Annual, Paper 1PhysicsMediumThermodynamics163× since 2002

Three perfect gases at absolute temperatures

{T_1},\,{T_2}

and

{T_3}

are mixed. The masses of molecules are

{m_1},{m_2}

and

{m_3}

and the number of molecules are

{n_1},

{n_2}

and

{n_3}

respectively. Assuming no loss of energy, the final temperature of the mixture is: