Atomic Structure: JEE Main 2026 Chemistry question

The work functions of two metals ($\mathrm{M_A}$ and $\mathrm{M_B}$) are in the 1 : 2 ratio. When these metals are exposed to photons of energy 6 eV, the kinetic energy of liberated electrons of $\mathrm{M_A}:\mathrm{M_B}$ is in the ratio of 2.642 : 1. The work functions (in eV) of $\mathrm{M_A}$ and $\mathrm{M_B}$ are respectively.