The vertices B and C of a Δ ABC lie on the line, (x + 2)/3 = (y - 1)/0 = z/4 such that BC = 5 units. Then the area (in sq. units) of this triangle, given that the point A(1, –1, 2), is:

Three Dimensional Geometry: JEE Main 2019 Mathematics question

JEE Main 2019 · 9 Apr, Evening shift · Q2489

JEE Main 20199 Apr, Evening shiftMathematicsHardThree Dimensional Geometry249× since 2002

The vertices B and C of a

\Delta

ABC lie on the line,

{{x + 2} \over 3} = {{y - 1} \over 0} = {z \over 4}

such that BC = 5 units. Then the area (in sq. units) of this triangle, given that the point A(1, –1, 2), is :

JEE Main 2019 · 9 Apr, Evening shift · Q2489

JEE Main 20199 Apr, Evening shiftMathematicsHardThree Dimensional Geometry249× since 2002

The vertices B and C of a

\Delta

ABC lie on the line,

{{x + 2} \over 3} = {{y - 1} \over 0} = {z \over 4}

such that BC = 5 units. Then the area (in sq. units) of this triangle, given that the point A(1, –1, 2), is :