JEE Main 202427 Jan, Evening shiftMathematicsMediumMatrices and Determinants245× since 2002The values of α\alphaα, for which ∣132α+32113α+132α+33α+10∣=0\left|\begin{array}{ccc}1 & \frac{3}{2} & \alpha+\frac{3}{2} \\ 1 & \frac{1}{3} & \alpha+\frac{1}{3} \\ 2 \alpha+3 & 3 \alpha+1 & 0\end{array}\right|=0112α+323313α+1α+23α+310=0, lie in the intervalAOption A. (−2,1)(-2,1)(−2,1)BOption B. (−32,32)\left(-\frac{3}{2}, \frac{3}{2}\right)(−23,23)COption C. (−3,0)(-3,0)(−3,0)DOption D. (0,3)(0,3)(0,3)CheckSkip · show solution
