JEE Main 202122 Jul, Evening shiftMathematicsMediumMatrices and Determinants245× since 2002The values of λ\lambdaλ and μ\muμ such that the system of equations x+y+z=6x + y + z = 6x+y+z=6, 3x+5y+5z=263x + 5y + 5z = 263x+5y+5z=26, x+2y+λz=μx + 2y + \lambda z = \mux+2y+λz=μ has no solution, are :AOption A. λ\lambdaλ = 3, μ\muμ = 5BOption B. λ\lambdaλ = 3, μ\muμ ≠\ne= 10COption C. λ\lambdaλ ≠\ne= 2, μ\muμ = 10DOption D. λ\lambdaλ = 2, μ\muμ ≠\ne= 10CheckSkip · show solution