JEE Main 201911 Jan, Morning shiftMathematicsMediumIntegral Calculus369× since 2002The value of the integral ∫−22sin2x[xπ]+12 dx\int\limits_{ - 2}^2 {{{{{\sin }^2}x} \over { \left[ {{x \over \pi }} \right] + {1 \over 2}}}} \,dx−2∫2[πx]+21sin2xdx (where [x] denotes the greatest integer less than or equal to x) isAOption A. 0BOption B. 4COption C. 4−-− sin 4DOption D. sin 4CheckSkip · show solution
