JEE Main 202227 Jun, Morning shiftMathematicsEasyIntegral Calculus369× since 2002The value of the integral ∫−22∣x3+x∣(ex∣x∣+1)dx\int\limits_{ - 2}^2 {{{|{x^3} + x|} \over {({e^{x|x|}} + 1)}}dx}−2∫2(ex∣x∣+1)∣x3+x∣dx is equal to :AOption A. 5e²BOption B. 3e^−-−2COption C. 4DOption D. 6CheckSkip · show solution
