JEE Main 20249 Apr, Evening shiftMathematicsEasyIntegral Calculus369× since 2002The value of the integral \int_\limits{-1}^2 \log _e\left(x+\sqrt{x^2+1}\right) d x isAOption A. 5−2+loge(7+451+2)\sqrt{5}-\sqrt{2}+\log _e\left(\frac{7+4 \sqrt{5}}{1+\sqrt{2}}\right)5−2+loge(1+27+45)BOption B. 2−5+loge(7+451+2)\sqrt{2}-\sqrt{5}+\log _e\left(\frac{7+4 \sqrt{5}}{1+\sqrt{2}}\right)2−5+loge(1+27+45)COption C. 5−2+loge(9+451+2)\sqrt{5}-\sqrt{2}+\log _e\left(\frac{9+4 \sqrt{5}}{1+\sqrt{2}}\right)5−2+loge(1+29+45)DOption D. 2−5+loge(9+451+2)\sqrt{2}-\sqrt{5}+\log _e\left(\frac{9+4 \sqrt{5}}{1+\sqrt{2}}\right)2−5+loge(1+29+45)CheckSkip · show solution
