JEE Main 20199 Apr, Evening shiftMathematicsHardIntegral Calculus369× since 2002The value of the integral ∫01xcot−1(1−x2+x4)dx\int\limits_0^1 {x{{\cot }^{ - 1}}(1 - {x^2} + {x^4})dx}0∫1xcot−1(1−x2+x4)dx is :-AOption A. π2−12loge2{\pi \over 2} - {1 \over 2}{\log _e}22π−21loge2BOption B. π4−loge2{\pi \over 4} - {\log _e}24π−loge2COption C. π4−12loge2{\pi \over 4} - {1 \over 2}{\log _e}24π−21loge2DOption D. π2−loge2{\pi \over 2} - {\log _e}22π−loge2CheckSkip · show solution
