The value of the integral ∫₁² ((t⁴ + 1)/(t⁶ + 1))dt is

(C) tan ⁻¹2 + 1/3 tan ⁻¹8 - (π)/3

(A) tan ⁻¹1/2 - 1/3 tan ⁻¹8 + (π)/3

(B) tan ⁻¹2 - 1/3 tan ⁻¹8 + (π)/3

(D) tan ⁻¹1/2 + 1/3 tan ⁻¹8 - (π)/3

Integral Calculus: JEE Main 2023 Mathematics question

JEE Main 2023 · 29 Jan, Evening shift · Q3453

JEE Main 202329 Jan, Evening shiftMathematicsMediumIntegral Calculus369× since 2002

The value of the integral

\int_1^2 {\left( {{{{t^4} + 1} \over {{t^6} + 1}}} \right)dt}

JEE Main 2023 · 29 Jan, Evening shift · Q3453

JEE Main 202329 Jan, Evening shiftMathematicsMediumIntegral Calculus369× since 2002

The value of the integral

\int_1^2 {\left( {{{{t^4} + 1} \over {{t^6} + 1}}} \right)dt}