JEE Main 202226 Jun, Morning shiftMathematicsMediumIntegral Calculus369× since 2002The value of the integral 48π4∫0π(3πx22−x3)sinx1+cos2xdx{{48} \over {{\pi ^4}}}\int\limits_0^\pi {\left( {{{3\pi {x^2}} \over 2} - {x^3}} \right){{\sin x} \over {1 + {{\cos }^2}x}}dx}π4480∫π(23πx2−x3)1+cos2xsinxdx is equal to __________.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution