JEE Main 20169 Apr, Morning shiftMathematicsMediumPermutations and Combinations98× since 2002The value of ∑r=115r2(15Cr15Cr−1)\sum\limits_{r = 1}^{15} {{r^2}} \left( {{{{}^{15}{C_r}} \over {{}^{15}{C_{r - 1}}}}} \right)r=1∑15r2(15Cr−115Cr) is equal to :AOption A. 560BOption B. 680COption C. 1240DOption D. 1085CheckSkip · show solution