JEE Main 202117 Mar, Morning shiftMathematicsEasyLimit, Continuity and Differentiability420× since 2002The value of limx→0+cos−1(x−[x]2).sin−1(x−[x]2)x−x3\mathop {\lim }\limits_{x \to {0^ + }} {{{{\cos }^{ - 1}}(x - {{[x]}^2}).{{\sin }^{ - 1}}(x - {{[x]}^2})} \over {x - {x^3}}}x→0+limx−x3cos−1(x−[x]2).sin−1(x−[x]2), where [ x ] denotes the greatest integer ≤\le≤ x is :AOption A. π\piπBOption B. π4{\pi \over 4}4πCOption C. π2{\pi \over 2}2πDOption D. 0CheckSkip · show solution
