JEE Main 202127 Jul, Evening shiftMathematicsHardLimit, Continuity and Differentiability420× since 2002The value of limx→0(x\root8\of1−sinx−\root8\of1+sinx)\mathop {\lim }\limits_{x \to 0} \left( {{x \over {\root 8 \of {1 - \sin x} - \root 8 \of {1 + \sin x} }}} \right)x→0lim(\root8\of1−sinx−\root8\of1+sinxx) is equal to :AOption A. 0BOption B. 4COption C. −-−4DOption D. −-−1CheckSkip · show solution
