JEE Main 202325 Jan, Morning shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002The value of limn→∞1+2−3+4+5−6 + ..... + (3n−2)+(3n−1)−3n2n4+4n+3−n4+5n+4\mathop {\lim }\limits_{n \to \infty } {{1 + 2 - 3 + 4 + 5 - 6\, + \,.....\, + \,(3n - 2) + (3n - 1) - 3n} \over {\sqrt {2{n^4} + 4n + 3} - \sqrt {{n^4} + 5n + 4} }}n→∞lim2n4+4n+3−n4+5n+41+2−3+4+5−6+.....+(3n−2)+(3n−1)−3n is :AOption A. 322{3 \over {2\sqrt 2 }}223BOption B. 32(2+1){3 \over 2}(\sqrt 2 + 1)23(2+1)COption C. 3(2+1)3(\sqrt 2 + 1)3(2+1)DOption D. 2+12{{\sqrt 2 + 1} \over 2}22+1CheckSkip · show solution
