JEE Main 202127 Jul, Morning shiftMathematicsEasyIntegral Calculus369× since 2002The value of limn→∞1n∑j=1n(2j−1)+8n(2j−1)+4n\mathop {\lim }\limits_{n \to \infty } {1 \over n}\sum\limits_{j = 1}^n {{{(2j - 1) + 8n} \over {(2j - 1) + 4n}}}n→∞limn1j=1∑n(2j−1)+4n(2j−1)+8n is equal to :AOption A. 5+loge(32)5 + {\log _e}\left( {{3 \over 2}} \right)5+loge(23)BOption B. 2−loge(23)2 - {\log _e}\left( {{2 \over 3}} \right)2−loge(32)COption C. 3+2loge(23)3 + 2{\log _e}\left( {{2 \over 3}} \right)3+2loge(32)DOption D. 1+2loge(32)1 + 2{\log _e}\left( {{3 \over 2}} \right)1+2loge(23)CheckSkip · show solution
