JEE Main 202125 Feb, Morning shiftMathematicsMediumIntegral Calculus369× since 2002The value of ∫−11x2e[x3]dx\int\limits_{ - 1}^1 {{x^2}{e^{[{x^3}]}}} dx−1∫1x2e[x3]dx, where [ t ] denotes the greatest integer ≤\le≤ t, is :AOption A. e+13{{e + 1} \over 3}3e+1BOption B. e−13e{{e - 1} \over {3e}}3ee−1COption C. 13e{1 \over {3e}}3e1DOption D. e+13e{{e + 1} \over {3e}}3ee+1CheckSkip · show solution
