JEE Main 20209 Jan, Morning shiftMathematicsMediumIntegral Calculus369× since 2002The value of ∫02πxsin8xsin8x+cos8xdx\int\limits_0^{2\pi } {{{x{{\sin }^8}x} \over {{{\sin }^8}x + {{\cos }^8}x}}} dx0∫2πsin8x+cos8xxsin8xdx is equal to :AOption A. 4π\piπBOption B. 2π\piπCOption C. π\piπ²DOption D. 2π\piπ²CheckSkip · show solution