The value of ∫₀¹ (8 log (1 + x))/(1 + x²) dx is

Integral Calculus: JEE Main 2011 Mathematics question

JEE Main 2011 · Annual, Paper 1 · Q3348

JEE Main 2011Annual, Paper 1MathematicsMediumIntegral Calculus369× since 2002

The value of

\int\limits_0^1 {{{8\log \left( {1 + x} \right)} \over {1 + {x^2}}}} dx

JEE Main 2011 · Annual, Paper 1 · Q3348

JEE Main 2011Annual, Paper 1MathematicsMediumIntegral Calculus369× since 2002

The value of

\int\limits_0^1 {{{8\log \left( {1 + x} \right)} \over {1 + {x^2}}}} dx