JEE Main 20262 Apr, Evening shiftMathematicsEasyIntegral Calculus369× since 2002The value of ∫020π(sin4x+cos4x) dx\int_0^{20\pi}(\sin^4x+\cos^4x)\,dx∫020π(sin4x+cos4x)dx is equal to :AOption A. 15π2\frac{15\pi}{2}215πBOption B. 25π25\pi25πCOption C. 15π15\pi15πDOption D. 25π2\frac{25\pi}{2}225πCheckSkip · show solution
