JEE Main 202623 Jan, Morning shiftMathematicsEasyBinomial Theorem and Its Simple Applications131× since 2002The value of 100C5051+100C5152+⋯+100C100101\frac{^{100}C_{50}}{51}+\frac{^{100}C_{51}}{52}+\cdots+\frac{^{100}C_{100}}{101}51100C50+52100C51+⋯+101100C100 is :AOption A. 2101101\frac{2^{101}}{101}1012101BOption B. 2101100\frac{2^{101}}{100}1002101COption C. 2100100\frac{2^{100}}{100}1002100DOption D. 2100101\frac{2^{100}}{101}1012100CheckSkip · show solution
