JEE Main 20244 Apr, Evening shiftMathematicsMediumSequence and Series179× since 2002The value of 1×22+2×32+…+100×(101)212×2+22×3+….+1002×101\frac{1 \times 2^2+2 \times 3^2+\ldots+100 \times(101)^2}{1^2 \times 2+2^2 \times 3+\ldots .+100^2 \times 101}12×2+22×3+….+1002×1011×22+2×32+…+100×(101)2 isAOption A. 305301\frac{305}{301}301305BOption B. 306305\frac{306}{305}305306COption C. 3231\frac{32}{31}3132DOption D. 3130\frac{31}{30}3031CheckSkip · show solution