JEE Main 20207 Jan, Evening shiftMathematicsMediumIntegral Calculus369× since 2002The value of α\alphaα for which 4α∫−12e−α∣x∣dx=54\alpha \int\limits_{ - 1}^2 {{e^{ - \alpha \left| x \right|}}dx} = 54α−1∫2e−α∣x∣dx=5, is:AOption A. loge2{\log _e}2loge2BOption B. loge2{\log _e}\sqrt 2loge2COption C. loge(43){\log _e}\left( {{4 \over 3}} \right)loge(34)DOption D. loge(32){\log _e}\left( {{3 \over 2}} \right)loge(23)CheckSkip · show solution
