JEE Main 2003Annual, Paper 1MathematicsEasyThree Dimensional Geometry249× since 2002The two lines x=ay+b,z=cy+dx=ay+b,z=cy+dx=ay+b,z=cy+d and x=a′y+b′,z=c′y+d′x = a'y + b',z = c'y + d'x=a′y+b′,z=c′y+d′ will be perpendicular, if and only if :AOption A. aa′+cc′+1=0aa' + cc' + 1 = 0aa′+cc′+1=0BOption B. aa′+bb′cc′+1=0aa' + bb'cc' + 1 = 0aa′+bb′cc′+1=0COption C. aa′+bb′cc′=0aa' + bb'cc' = 0aa′+bb′cc′=0DOption D. (a+a′)(b+b′)+(c+c′)=0\left( {a + a'} \right)\left( {b + b'} \right) + \left( {c + c'} \right) = 0(a+a′)(b+b′)+(c+c′)=0CheckSkip · show solution
