JEE Main 2006Annual, Paper 1MathematicsEasyThree Dimensional Geometry249× since 2002The two lines x=ay+b,z=cy+d;x=ay+b, z=cy+d;x=ay+b,z=cy+d; and x=a′y+b′,x=a'y+b' ,x=a′y+b′, z=c′y+d′z=c'y+d'z=c′y+d′ are perpendicular to each other if :AOption A. aa′+cc′=−1aa'+cc'=-1aa′+cc′=−1BOption B. aa′+cc′=1aa'+cc'=1aa′+cc′=1COption C. aa′+cc′=−1{a \over {a'}} + {c \over {c'}} = - 1a′a+c′c=−1DOption D. aa′+cc′=1{a \over {a'}} + {c \over {c'}} = 1a′a+c′c=1CheckSkip · show solution
