The trajectory of projectile, projected from the ground is given by y=x-(x²)/20. Where x and y are measured in meter. The maximum height attained by the projectile will be.

Kinematics: JEE Main 2023 Physics question

JEE Main 2023 · 8 Apr, Evening shift · Q7804

JEE Main 20238 Apr, Evening shiftPhysicsMediumKinematics177× since 2002

The trajectory of projectile, projected from the ground is given by

y=x-\frac{x^{2}}{20}

. Where

x

and

y

are measured in meter. The maximum height attained by the projectile will be.

JEE Main 2023 · 8 Apr, Evening shift · Q7804

JEE Main 20238 Apr, Evening shiftPhysicsMediumKinematics177× since 2002

The trajectory of projectile, projected from the ground is given by

y=x-\frac{x^{2}}{20}

. Where

x

and

y

are measured in meter. The maximum height attained by the projectile will be.