JEE Main 202427 Jan, Evening shiftPhysicsHardThermodynamics163× since 2002The total kinetic energy of 1 mole of oxygen at 27∘C27^{\circ} \mathrm{C}27∘C is : [Use universal gas constant (R)=8.31 J/(R)=8.31 \mathrm{~J} /(R)=8.31 J/ mole K]AOption A. 6232.5 JBOption B. 5670.5 JCOption C. 6845.5 JDOption D. 5942.0 JCheckSkip · show solution
