The temperature of a gas is -78^(°) C and the average translational kinetic energy of its molecules is K. The temperature at which the average translational kinetic energy of the molecules of the same gas becomes 2 ~K is:

Thermodynamics: JEE Main 2024 Physics question

JEE Main 2024 · 9 Apr, Evening shift · Q7435

JEE Main 20249 Apr, Evening shiftPhysicsHardThermodynamics163× since 2002

The temperature of a gas is

-78^{\circ} \mathrm{C}

and the average translational kinetic energy of its molecules is

\mathrm{K}

. The temperature at which the average translational kinetic energy of the molecules of the same gas becomes

2 \mathrm{~K}

is :

JEE Main 2024 Thermodynamics Question with Solution (9 Apr Evening shift, Q7435) | JEE Arc