Chemical Kinetics: JEE Main 2026 Chemistry question

JEE Main 2026 · 22 Jan, Morning shift · Q71

JEE Main 202622 Jan, Morning shiftChemistryMediumChemical Kinetics62× since 2002

The temperature at which the rate constants of the given below two gaseous reactions become equal is ______ K. (Nearest integer)

\mathrm{X\rightarrow Y}

k_1=10^{6}e^{-\frac{30000}{T}}

;

\mathrm{P\rightarrow Q}

k_2=10^{4}e^{-\frac{24000}{T}}

. Given:

\ln10=2.303

Your answerType your answer. Integers and decimals are accepted.

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JEE Main 2026 Chemical Kinetics Question with Solution (22 Jan Morning shift, Q71) | JEE Arc

JEE Main 2026 · 22 Jan, Morning shift · Q71

JEE Main 202622 Jan, Morning shiftChemistryMediumChemical Kinetics62× since 2002

The temperature at which the rate constants of the given below two gaseous reactions become equal is ______ K. (Nearest integer)

\mathrm{X\rightarrow Y}

k_1=10^{6}e^{-\frac{30000}{T}}

;

\mathrm{P\rightarrow Q}

k_2=10^{4}e^{-\frac{24000}{T}}

. Given:

\ln10=2.303

Your answerType your answer. Integers and decimals are accepted.