JEE Main 202126 Feb, Evening shiftMathematicsMediumSequence and Series179× since 2002The sum of the series ∑n=1∞n2+6n+10(2n+1)!\sum\limits_{n = 1}^\infty {{{{n^2} + 6n + 10} \over {(2n + 1)!}}}n=1∑∞(2n+1)!n2+6n+10 is equal to :AOption A. 418e+198e−1−10{{41} \over 8}e + {{19} \over 8}{e^{ - 1}} - 10841e+819e−1−10BOption B. 418e−198e−1−10{{41} \over 8}e - {{19} \over 8}{e^{ - 1}} - 10841e−819e−1−10COption C. 418e+198e−1+10{{41} \over 8}e + {{19} \over 8}{e^{ - 1}} + 10841e+819e−1+10DOption D. −418e+198e−1−10- {{41} \over 8}e + {{19} \over 8}{e^{ - 1}} - 10−841e+819e−1−10CheckSkip · show solution
