JEE Main 2003Annual, Paper 1MathematicsMediumSequence and Series179× since 2002The sum of the serier 11.2−12.3+13.4..............{1 \over {1.2}} - {1 \over {2.3}} + {1 \over {3.4}}..............1.21−2.31+3.41.............. up to ∞\infty∞ is equal toAOption A. log e(4e) \log {\,_e}\left( {{4 \over e}} \right)\,\,loge(e4)BOption B. 2 log e22\,\log {\,_e}22loge2COption C. log e2−1 \log {\,_e}2 - 1\,loge2−1DOption D. log e2\log {\,_e}2loge2CheckSkip · show solution
